ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:56Z
7φ² + 7φ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
302K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 9 7 ; 3 10 | = 69
91K
9n² + 8n + 4 = 0
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
311K
E = mc²
det| 5 5 ; 0 6 | = 30
det| 6 6 ; 3 7 | = 24
364K
det| 9 4 ; 1 10 | = 86
6K