ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 16:56Z
∇²β = 0
det| 7 4 ; 4 8 | = 40
259K
11y² + 3y + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
159K
∑_{k=1}^{n} k = n(n+1)/2
270K
∇ × E = −∂B/∂t
det| 11 9 ; 5 12 | = 87
437K
\lim_{x\to 0} \frac{\sin x}{x} = 1