ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:53Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
91K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 7 4 ; 4 8 | = 40
264K
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
det| 6 6 ; 3 7 | = 24
39K
10r² + 7r + 5 = 0