ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:48Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 12 9 ; 5 13 | = 111
310K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
2H₂ + O₂ → 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
68K
10r² + 7r + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
364K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
6K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
λ = h/p