ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:26Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 4 ; 4 8 | = 40
302K
∫₀^∞ e^(-r²) dr = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
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12γ² + 2γ + 2 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 9 7 ; 3 10 | = 69
310K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
311K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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λ = h/p
det| 1 4 ; 3 2 | = -10
68K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O