ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:43Z
7φ² + 7φ + 6 = 0
det| 9 4 ; 1 10 | = 86
312K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
125K
9n² + 8n + 4 = 0
\lim_{y\to 0} \frac{\sin y}{y} = 1
17K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
310K
ΔS ≥ 0
\frac{8}{6} \sum_{i=1}^{n} i^{2}
311K
E = mc²
det| 10 4 ; 1 11 | = 106
68K
AgNO₃ + NaCl → AgCl↓ + NaNO₃