ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 19:12Z
d/dr [r^5] = 5r^4
∑_{k=1}^{n} k = n(n+1)/2
302K
det| 9 4 ; 1 10 | = 86
312K
2x² + 4x + 1 = 0
∫₀^∞ e^(-x²) dx = √π / 2
91K
2H₂ + O₂ → 2H₂O
det| 11 7 ; 6 12 | = 90
det| 11 5 ; 0 12 | = 132
311K
7ω² + 6ω + 0 = 0
6r² + 5r + 0 = 0
E = mc²