ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:28Z
10n² + 5n + 0 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
91K
det| 8 7 ; 7 9 | = 23
Fe₂O₃ + 3CO → 2Fe + 3CO₂
17K
∑_{k=1}^{n} k = n(n+1)/2
310K
d/dt [t^11] = 11t^10
det| 7 4 ; 4 8 | = 40
311K
det| 2 3 ; 5 3 | = -9
264K
∫₀^∞ e^(-y²) dy = √π / 2