ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:11Z
iħ ∂ψ/∂t = Ĥψ
\lim_{t\to 0} \frac{\sin t}{t} = 1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
270K
∇²t = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
437K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
5ω² + 9ω + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
202K
∫₀^∞ e^(-α²) dα = √π / 2
\lim_{α\to 0} \frac{\sin α}{α} = 1
479K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 8 1 ; 7 9 | = 65
12α² + 9α + 0 = 0