ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:23Z
∑_{k=1}^{n} k = n(n+1)/2
4β² + 5β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
125K
det| 2 7 ; 7 3 | = -43
91K
d/dφ [φ^6] = 6φ^5
∑_{k=1}^{n} k = n(n+1)/2
17K
6n² + 3n + 0 = 0
10β² + 6β + 6 = 0
det| 9 4 ; 1 10 | = 86
68K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
39K
F = ma
∫₀^∞ e^(-θ²) dθ = √π / 2
364K
d/dα [α^1] = 1α^0