ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:26Z
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
312K
12φ² + 6φ + 4 = 0
det| 3 7 ; 2 4 | = -2
91K
2H₂ + O₂ → 2H₂O
5φ² + 5φ + 0 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
311K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
\frac{6}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
det| 7 7 ; 5 8 | = 21
ΔS ≥ 0
∫₀^∞ e^(-β²) dβ = √π / 2
e^{i\pi} + 1 = 0