ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:27Z
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-t²) dt = √π / 2
312K
12φ² + 6φ + 4 = 0
det| 7 1 ; 7 8 | = 49
125K
2H₂ + O₂ → 2H₂O
5φ² + 5φ + 0 = 0
\frac{6}{8} \sum_{i=1}^{n} i^{2}
det| 1 2 ; 7 2 | = -12
68K
det| 1 4 ; 3 2 | = -10
39K
det| 1 8 ; 4 2 | = -30
364K