ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:52Z
7φ² + 7φ + 6 = 0
det| 9 4 ; 1 10 | = 86
302K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
9n² + 8n + 4 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
17K
det| 1 2 ; 7 2 | = -12
310K
ΔS ≥ 0
det| 9 7 ; 3 10 | = 69
311K
∫₀^∞ e^(-ω²) dω = √π / 2
264K
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
68K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 5 ; 0 6 | = 30
det| 3 5 ; 7 4 | = -23
F = ma
∇²y = 0