ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:58Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
302K
det| 7 4 ; 4 8 | = 40
312K
4β² + 5β + 0 = 0
det| 3 7 ; 2 4 | = -2
125K
d/dφ [φ^6] = 6φ^5
Fe₂O₃ + 3CO → 2Fe + 3CO₂
17K
6n² + 3n + 0 = 0
det| 2 7 ; 7 3 | = -43
311K
CH₄ + 2O₂ → CO₂ + 2H₂O
264K
10β² + 6β + 6 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
68K
4β² + 3β + 0 = 0
F = ma