ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 02:02Z
4α² + 9α + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
312K
∫₀^∞ e^(-y²) dy = √π / 2
det| 11 5 ; 0 12 | = 132
125K
det| 1 9 ; 6 2 | = -52
det| 9 4 ; 1 10 | = 86
310K
∑_{k=1}^{n} k = n(n+1)/2
d/dz [z^11] = 11z^10
264K
CH₄ + 2O₂ → CO₂ + 2H₂O
68K
∑_{k=1}^{n} k = n(n+1)/2
364K