ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 18:59Z
det| 11 6 ; 6 12 | = 96
det| 11 2 ; 5 12 | = 122
259K
∑_{k=1}^{n} k = n(n+1)/2
257K
F = ma
det| 9 4 ; 3 10 | = 78
∑_{k=1}^{n} k = n(n+1)/2
22K
det| 4 8 ; 0 5 | = 20
479K
det| 7 4 ; 4 8 | = 40
205K