ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:48Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 12 9 ; 5 13 | = 111
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∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
311K
det| 7 4 ; 4 8 | = 40
264K