ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:47Z
7φ² + 7φ + 6 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
125K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
91K
9n² + 8n + 4 = 0
\lim_{α\to 0} \frac{\sin α}{α} = 1
17K
ΔS ≥ 0
det| 9 4 ; 1 10 | = 86
311K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
264K
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃