ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:27Z
10n² + 5n + 0 = 0
det| 4 8 ; 0 5 | = 20
302K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
125K
\frac{11}{6} \sum_{i=1}^{n} i^{2}
91K
det| 8 7 ; 7 9 | = 23
Fe₂O₃ + 3CO → 2Fe + 3CO₂
17K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
310K
d/dt [t^11] = 11t^10
\lim_{t\to 0} \frac{\sin t}{t} = 1
311K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
det| 7 4 ; 4 8 | = 40
68K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
39K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
364K