ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:09Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
310K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∫₀^∞ e^(-n²) dn = √π / 2
264K
2H₂ + O₂ → 2H₂O
10r² + 7r + 5 = 0
det| 11 2 ; 5 12 | = 122
364K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
6K