ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:10Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
∫₀^∞ e^(-α²) dα = √π / 2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
453K
7y² + 6y + 1 = 0
det| 7 4 ; 4 8 | = 40
177K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
207K
∇²y = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
333K
6r² + 8r + 4 = 0
det| 5 3 ; 2 6 | = 24
115K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∫₀^∞ e^(-β²) dβ = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂