ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:25Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
312K
∫₀^∞ e^(-r²) dr = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃
125K
det| 7 4 ; 4 8 | = 40
91K
12γ² + 2γ + 2 = 0
E = mc²
det| 11 2 ; 5 12 | = 122
264K
λ = h/p
det| 12 9 ; 5 13 | = 111
68K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O