ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:28Z
N₂ + 3H₂ ⇌ 2NH₃
12φ² + 6φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
125K
det| 9 4 ; 1 10 | = 86
91K
2H₂ + O₂ → 2H₂O
det| 12 1 ; 5 13 | = 151
310K
5φ² + 5φ + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
311K
\frac{6}{8} \sum_{i=1}^{n} i^{2}
det| 3 7 ; 2 4 | = -2
68K
ΔS ≥ 0
∫₀^∞ e^(-n²) dn = √π / 2
364K
e^{i\pi} + 1 = 0
det| 10 7 ; 6 11 | = 68