ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:49Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
det| 3 1 ; 7 4 | = 5
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∑_{k=1}^{n} k = n(n+1)/2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 6 6 ; 3 7 | = 24
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det| 9 4 ; 1 10 | = 86
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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