ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 19:03Z
d/dr [r^5] = 5r^4
2x² + 4x + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
125K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-β²) dβ = √π / 2
310K
det| 11 7 ; 6 12 | = 90
det| 11 9 ; 5 12 | = 87
311K
det| 7 4 ; 4 8 | = 40
264K
7ω² + 6ω + 0 = 0
6r² + 5r + 0 = 0