ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:41Z
7φ² + 7φ + 6 = 0
det| 4 6 ; 0 5 | = 20
302K
∫₀^∞ e^(-ψ²) dψ = √π / 2
312K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
125K
∑_{k=1}^{n} k = n(n+1)/2
91K
9n² + 8n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
17K
ΔS ≥ 0
E = mc²
det| 9 4 ; 1 10 | = 86
68K
det| 5 5 ; 0 6 | = 30
∑_{k=1}^{n} k = n(n+1)/2
364K
det| 3 5 ; 7 4 | = -23