ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:53Z
7φ² + 7φ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
302K
∫₀^∞ e^(-t²) dt = √π / 2
312K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 9 ; 7 6 | = -33
91K
9n² + 8n + 4 = 0
ΔS ≥ 0
det| 9 4 ; 1 10 | = 86
311K
E = mc²