ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:24Z
10n² + 5n + 0 = 0
det| 5 6 ; 4 6 | = 6
302K
∑_{k=1}^{n} k = n(n+1)/2
312K
E = mc²
det| 8 7 ; 7 9 | = 23
det| 7 4 ; 4 8 | = 40
17K
det| 10 4 ; 1 11 | = 106
310K
d/dt [t^11] = 11t^10
∑_{k=1}^{n} k = n(n+1)/2
311K
det| 9 2 ; 3 10 | = 84
264K
∫₀^∞ e^(-y²) dy = √π / 2