ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:27Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
302K
12φ² + 6φ + 4 = 0
det| 12 1 ; 5 13 | = 151
91K
2H₂ + O₂ → 2H₂O
5φ² + 5φ + 0 = 0
det| 7 4 ; 4 8 | = 40
264K
\frac{6}{8} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-θ²) dθ = √π / 2
39K
ΔS ≥ 0
det| 9 1 ; 7 10 | = 83
364K