ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:55Z
10n² + 5n + 0 = 0
E = mc²
det| 10 9 ; 0 11 | = 110
91K
det| 8 7 ; 7 9 | = 23
det| 11 9 ; 5 12 | = 87
17K
det| 7 4 ; 4 8 | = 40
310K
d/dt [t^11] = 11t^10
∑_{k=1}^{n} k = n(n+1)/2
264K
∫₀^∞ e^(-y²) dy = √π / 2
det| 5 6 ; 1 6 | = 24
68K
det| 4 8 ; 1 5 | = 12
det| 9 8 ; 3 10 | = 66
364K
\oint_C \vec{F}\cdot d\vec{r} = 0
N₂ + 3H₂ ⇌ 2NH₃
AgNO₃ + NaCl → AgCl↓ + NaNO₃