ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:26Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
302K
4β² + 5β + 0 = 0
det| 5 6 ; 4 6 | = 6
125K
det| 10 9 ; 0 11 | = 110
91K
d/dφ [φ^6] = 6φ^5
det| 9 8 ; 3 10 | = 66
310K
6n² + 3n + 0 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
68K
det| 7 4 ; 4 8 | = 40
39K