ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:35Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
312K
∫₀^∞ e^(-r²) dr = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
91K
12γ² + 2γ + 2 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
17K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
264K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
39K