ChemCalc Dump /sym/e2195f
id=20336 · host=br.gridbatch.net · 2026-09-03 03:51Z
det| 2 3 ; 0 3 | = 6
\oint_C \vec{F}\cdot d\vec{r} = 0
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\oint_C \vec{F}\cdot d\vec{r} = 0
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∇ × E = −∂B/∂t
det| 11 4 ; 6 12 | = 108
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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∂z/∂x = 9z
CaCO₃ → CaO + CO₂
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∂r/∂α = 8r
E = mc²
3ψ² + 5ψ + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}