ChemCalc Dump /sym/560fdb
id=251634 · host=br.gridbatch.net · 2026-09-03 03:55Z
F = G m₁m₂ / r²
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
9t² + 4t + 0 = 0
d/dz [z^1] = 1z^0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
det| 12 7 ; 3 13 | = 135
\oint_C \vec{F}\cdot d\vec{r} = 0
3ω² + 1ω + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
F = G m₁m₂ / r²
∑_{k=1}^{n} k = n(n+1)/2
3y² + 9y + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}