ChemCalc Dump /sym/0816f8
id=284571 · host=br.gridbatch.net · 2026-09-03 04:10Z
∇ × E = −∂B/∂t
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
11φ² + 4φ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
\lim_{α\to 0} \frac{\sin α}{α} = 1
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 7 9 ; 1 8 | = 47
3θ² + 6θ + 5 = 0
∂r/∂ω = 6r
λ = h/p
det| 1 4 ; 4 2 | = -14
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1