ChemCalc Dump /sym/e08d0c
id=311595 · host=br.gridbatch.net · 2026-09-03 04:10Z
∫₀^∞ e^(-ψ²) dψ = √π / 2
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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5z² + 7z + 3 = 0
9ω² + 5ω + 6 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
9α² + 3α + 7 = 0
e^{i\pi} + 1 = 0
det| 6 1 ; 1 7 | = 41
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2