ChemCalc Dump /sym/f34a71
id=315293 · host=br.gridbatch.net · 2026-09-03 03:56Z
\oint_C \vec{F}\cdot d\vec{r} = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
∇ × E = −∂B/∂t
4θ² + 3θ + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
CaCO₃ → CaO + CO₂
iħ ∂ψ/∂t = Ĥψ
Fe₂O₃ + 3CO → 2Fe + 3CO₂
E = mc²
∇²φ = 0
F = ma
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 9 1 ; 0 10 | = 90