ChemCalc Dump /sym/51b06c
id=331754 · host=br.gridbatch.net · 2026-09-03 04:13Z
∇ × E = −∂B/∂t
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
1n² + 7n + 4 = 0
∂β/∂β = 2β
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
e^{i\pi} + 1 = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
6n² + 3n + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\oint_C \vec{F}\cdot d\vec{r} = 0
6θ² + 2θ + 0 = 0
d/dr [r^1] = 1r^0
d/dψ [ψ^1] = 1ψ^0