ChemCalc Dump /sym/64680e
id=401983 · host=br.gridbatch.net · 2026-09-03 04:11Z
∑_{k=1}^{n} k = n(n+1)/2
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
12n² + 6n + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
\oint_C \vec{F}\cdot d\vec{r} = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 1 ; 2 8 | = 54
det| 6 9 ; 4 7 | = 6
det| 5 7 ; 7 6 | = -19
e^{i\pi} + 1 = 0
∂α/∂α = 3α
ΔS ≥ 0