ChemCalc Dump /sym/b655e8

id=408026 · host=br.gridbatch.net · 2026-09-03 04:03Z

det| 5 6 ; 1 6 | = 24

\oint_C \vec{F}\cdot d\vec{r} = 0

252K

\oint_C \vec{F}\cdot d\vec{r} = 0

464K

PV = nRT

PV = nRT

32K

∂z/∂φ = 7z

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8t² + 6t + 2 = 0

e^{i\pi} + 1 = 0

223K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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PV = nRT

ΔS ≥ 0

λ = h/p

∫₀^∞ e^(-n²) dn = √π / 2

det| 4 9 ; 6 5 | = -34

8z² + 3z + 1 = 0

∇²n = 0

∂r/∂φ = 5r