ChemCalc Dump /sym/0d74af

id=417121 · host=br.gridbatch.net · 2026-09-03 03:57Z

det| 3 8 ; 5 4 | = -28

\oint_C \vec{F}\cdot d\vec{r} = 0

252K

\oint_C \vec{F}\cdot d\vec{r} = 0

464K

λ = h/p

PV = nRT

32K

∂z/∂φ = 7z

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10r² + 7r + 1 = 0

e^{i\pi} + 1 = 0

223K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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∫₀^∞ e^(-x²) dx = √π / 2

PV = nRT

2H₂ + O₂ → 2H₂O

∇²t = 0

det| 1 3 ; 4 2 | = -10

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

∇ × E = −∂B/∂t

F = G m₁m₂ / r²