ChemCalc Dump /sym/3c9748
id=434414 · host=br.gridbatch.net · 2026-09-03 04:05Z
∇²β = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
4φ² + 6φ + 4 = 0
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
\lim_{β\to 0} \frac{\sin β}{β} = 1
10ω² + 5ω + 3 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 2 8 ; 0 3 | = 6
5ψ² + 1ψ + 0 = 0
9β² + 4β + 6 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∇²θ = 0