ChemCalc Dump /sym/2b7173
id=447482 · host=br.gridbatch.net · 2026-09-03 04:08Z
∫₀^∞ e^(-ω²) dω = √π / 2
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
11y² + 9y + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
e^{i\pi} + 1 = 0
12t² + 9t + 2 = 0
\lim_{z\to 0} \frac{\sin z}{z} = 1
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
∫₀^∞ e^(-γ²) dγ = √π / 2
λ = h/p
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 7 5 ; 1 8 | = 51