ChemCalc Dump /sym/0f9b29
id=529312 · host=br.gridbatch.net · 2026-09-03 04:11Z
∑_{k=1}^{n} k = n(n+1)/2
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
\lim_{z\to 0} \frac{\sin z}{z} = 1
E = mc²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
\lim_{α\to 0} \frac{\sin α}{α} = 1
e^{i\pi} + 1 = 0
11φ² + 4φ + 2 = 0
10t² + 6t + 2 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 6 1 ; 5 7 | = 37
ΔS ≥ 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂