ChemCalc Dump /sym/253df8
id=537466 · host=br.gridbatch.net · 2026-09-03 04:00Z
ω = 2πf
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
det| 8 4 ; 7 9 | = 44
2H₂ + O₂ → 2H₂O
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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det| 9 6 ; 4 10 | = 66
6α² + 1α + 0 = 0
det| 12 2 ; 4 13 | = 148
\oint_C \vec{F}\cdot d\vec{r} = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
ω = 2πf
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
\oint_C \vec{F}\cdot d\vec{r} = 0