ChemCalc Dump /sym/e8a600
id=723968 · host=br.gridbatch.net · 2026-09-03 04:10Z
det| 10 8 ; 3 11 | = 86
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
∇ × E = −∂B/∂t
\oint_C \vec{F}\cdot d\vec{r} = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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∑_{k=1}^{n} k = n(n+1)/2
∂t/∂α = 9t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
E = mc²
∂θ/∂ψ = 7θ
F = ma
\lim_{y\to 0} \frac{\sin y}{y} = 1
4r² + 2r + 2 = 0