ChemCalc Dump /sym/d5069b
id=766796 · host=br.gridbatch.net · 2026-09-03 03:59Z
∇ × E = −∂B/∂t
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
11θ² + 5θ + 0 = 0
2β² + 1β + 3 = 0
det| 2 9 ; 7 3 | = -57
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 10 9 ; 5 11 | = 65
\binom{n}{k} = \frac{n!}{k!(n-k)!}
F = ma
ΔS ≥ 0