ChemCalc Dump /sym/122997
id=868674 · host=br.gridbatch.net · 2026-09-03 04:07Z
det| 3 9 ; 4 4 | = -24
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
ΔS ≥ 0
11r² + 5r + 5 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
PV = nRT
∇²t = 0
PV = nRT
∇ × E = −∂B/∂t
\lim_{β\to 0} \frac{\sin β}{β} = 1
det| 6 4 ; 6 7 | = 18
ΔS ≥ 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O