ChemCalc Dump /sym/f28864
id=885562 · host=br.gridbatch.net · 2026-09-03 04:13Z
∑_{k=1}^{n} k = n(n+1)/2
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
2γ² + 1γ + 6 = 0
∇²z = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
2r² + 4r + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 4 6 ; 6 5 | = -16
11ω² + 8ω + 0 = 0
CaCO₃ → CaO + CO₂
∑_{k=1}^{n} k = n(n+1)/2
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
5z² + 5z + 0 = 0