ChemCalc Dump /sym/b27983
id=886882 · host=br.gridbatch.net · 2026-09-03 04:13Z
∫₀^∞ e^(-ω²) dω = √π / 2
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
\lim_{z\to 0} \frac{\sin z}{z} = 1
F = G m₁m₂ / r²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 10 8 ; 4 11 | = 78
4θ² + 2θ + 2 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
4γ² + 8γ + 5 = 0